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3x^2+25x=11
We move all terms to the left:
3x^2+25x-(11)=0
a = 3; b = 25; c = -11;
Δ = b2-4ac
Δ = 252-4·3·(-11)
Δ = 757
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-\sqrt{757}}{2*3}=\frac{-25-\sqrt{757}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+\sqrt{757}}{2*3}=\frac{-25+\sqrt{757}}{6} $
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